0.05 kg ভরের পানিকে 0°C তাপমাত্রা থেকে 20°C তাপমাত্রায় উত্তপ্ত করা হলো। এন্ট্রপির পরিবর্তন কত?

The correct answer to the question regarding the change in entropy when heating water from 0°C to 20°C is $14.85 J{K}^{-1}$.

This result is derived using the formula for the change in entropy (ΔS) of a substance when it is heated, which can be expressed as:

  
• ΔS = m * c * ln(Tf/Ti)

Where:

  
• m = mass of the water (0.05 kg)
  
• c = specific heat capacity of water (approximately 4.18 kJ/kg·K)
  
• Tf = final temperature (20°C or 293 K)
  
• Ti = initial temperature (0°C or 273 K)

In this case, when you calculate the change in temperature and apply the values, the calculated entropy change comes out to be approximately 14.85 J/K, which matches the given answer.

Thus, the reasoning and calculations behind it show that the answer is correct.

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