Mr X will be the Chairman of the committee . In how many ways can a committee of 5 member be chosen from a total o f8 people given that Mr. Z must be one them?
Created: 2 years ago |
Updated: 8 months ago
best des
If Mr. Z must be one of the committee members, we need to choose the remaining 4 members from the remaining 7 people (excluding Mr. Z).
This can be calculated using combinations (n choose k), where n is the total number of people to choose from, and k is the number of people to choose. In this case, n = 7 (excluding Mr. Z) and k = 4.
So, the number of ways to choose the remaining 4 members is:
7 choose 4 = C(7, 4) = (7! / (4!(7-4)!)) = (7! / (4! * 3!)) = (7 * 6 * 5) / (3 * 2 * 1) = 35
Therefore, there are 35 ways to choose the remaining 4 members of the committee when Mr. Z must be one of them.
Related Question
View More
Created: 6 years ago |
Updated: 3 weeks ago
Created: 6 years ago |
Updated: 3 weeks ago
Created: 6 years ago |
Updated: 3 weeks ago
Created: 6 years ago |
Updated: 3 days ago
Created: 6 years ago |
Updated: 3 weeks ago
Promotion
Download Our Mobile Apps
