If A and B together can complete a piece of work in 15 days and B alone in 20 days, in how many days can A alone complete the work?
Let's denote the work done by A in one day as "a" and the work done by B in one day as "b."
We are given the following information:
- A and B together can complete a piece of work in 15 days, so their combined work rate is 1/15 per day.
- B alone can complete the same work in 20 days, so B's work rate is 1/20 per day.
Now, we can set up an equation based on their combined work rate:
a + b = 1/15
We need to find the work rate of A alone, which is "a." To do that, we can solve for "a" in the equation:
a = 1/15 - b
Now, we'll substitute the value of "b" from the second piece of information (B's work rate) into this equation:
a = 1/15 - 1/20
To subtract these fractions, we need a common denominator, which is 60:
a = (4/60) - (3/60) a = (1/60)
So, A's work rate is 1/60 per day.
Now, we can find how many days A alone would take to complete the work:
A alone would take 1 work unit per (1/60) days.
1 work unit per (1/60) days = 60 work units per day.
Therefore, A alone can complete the work in 60 days.
ঐকিক নিয়ম (Unitary Methods):
একটি জিনিসের দাম, ওজন, পরিমাণ ইত্যাদি বের করে নির্দিষ্ট সংখ্যক এই জাতীয় জিনিসের দাম, ওজন, পরিমাণ ইত্যাদি বের করার নিয়মকে ঐকিক নিয়ম বলে।
Related Question
View MorePromotion
Download Our Mobile Apps
