The persons, X & Y, are standing 50 yards apart on a North-South axis. X walks 65 yards to west and Y walks 55 yards to the East and both stop. Find the straight line distance in yeards between these two positions?
Created: 6 years ago |
Updated: 8 months ago
best des
To find the straight-line distance between the final positions of persons X and Y, we can use the Pythagorean theorem because they have moved in perpendicular directions (west and east) along a North-South axis. Let's denote the initial positions as X(0, 0) and Y(0, 50) and their final positions as X'(65, 0) and Y'(-55, 50).
The distance formula for two points (x1, y1) and (x2, y2) in a plane is:
Distance = √((x2 - x1)² + (y2 - y1)²)
For X and Y:
Distance = √((65 - (-55))² + (0 - 50)²) Distance = √((65 + 55)² + (-50)²) Distance = √(120² + (-50)²) Distance = √(14400 + 2500) Distance = √16900 Distance = 130 yards
So, the straight-line distance between the final positions of X and Y is 130 yards.
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