Six consecutive whole numbers are given. The sum of the first three numbers is 27. What is the sum of the last three numbers?
Created: 6 years ago |
Updated: 2 years ago
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Let the numbers be x,x + 1,x + 2, x + 3,x + 4,x + 5
So now ATQ,
x + x + 1 + x + 2 = 27
So that's equal to 3x + 3 = 27
which is equal to x + 1 = 9.
So x = 8
Now the sum of other three numbers = x + 3 + x + 4 + x + 5 = 3x + 12 = 3*8 + 12 = 24 + 12 = 36
Hence Answer is 36
Md Azizur Rahman
Founder of Satt
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