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y = mx,

y = m_{1} x

\frac{1}{2 b^{2}} (m - m_{1})

\frac{b^{2}}{2} (\frac{1}{m} - \frac{1}{m^{1}})

2 b (\frac{1}{m^{1}} - \frac{1}{m})

\frac{1}{2 b} (m_{1} - m)

ANS : 2

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