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1^{3} + 3^{3} + 5^{3} + . . . + (2 n - 1)^{3} = ?

n(2n+1)

\frac{n (n - 1) (2 n + 1)}{6}

n^{2} (2 n^{2} - 1)

\frac{n (2 n - 1)}{6}

ANS : 3

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