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Question
একটি কোষের তড়িৎচালক শক্তি 1.5 v এবং আভ্যন্তরীন রোধ
2
ω
। এর প্রান্তদ্বয়
10
ω
রোধের তার দ্বারা যুক্ত করলে কত তড়িৎ প্রবাহিত হবে?
0.125 A
1.0 A
1.125 A
2.125 A
ANSWER : 1
Descrption
<p>আমরা জানি, <math xmlns="http://www.w3.org/1998/Math/MathML"><mi mathvariant="normal">I</mi><mo>=</mo><mfrac><mi mathvariant="normal">E</mi><mrow><mi mathvariant="normal">R</mi><mo>+</mo><mi mathvariant="normal">r</mi></mrow></mfrac></math><br>সুতরাং, <math xmlns="http://www.w3.org/1998/Math/MathML"><mi mathvariant="normal">I</mi><mo>=</mo><mfrac><mrow><mn>1</mn><mo>.</mo><mn>5</mn></mrow><mrow><mn>10</mn><mo>+</mo><mn>2</mn></mrow></mfrac><mo>=</mo><mfrac><mrow><mn>1</mn><mo>.</mo><mn>5</mn></mrow><mn>12</mn></mfrac><mo>=</mo><mn>0</mn><mo>.</mo><mn>125</mn><mi mathvariant="normal">A</mi></math><br> </p><p>এখানে, I = তড়িৎ প্রবাহ<br>E = কোষের তড়িৎচালক শক্তি<br>R = বাহ্যিক রোধ<br>r = অভ্যন্তরীণ রোধ</p>
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