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Question

The diagonal of a square is

4 \sqrt{2}

cm. The diagonal of another square whose area is double that of the first square , is:

8cm

8 \sqrt{2 c m}

4 \sqrt{2 c m}

16 cm

ANSWER : 1

Descrption

<pre>diagonal  =  <math xmlns = "http://www.w3.org/1998/Math/MathML"><mi>a</mi><msqrt><mn>2</mn></msqrt><mo> = </mo><mn>4</mn><msqrt><mn>2</mn></msqrt></math>
<math xmlns = "http://www.w3.org/1998/Math/MathML"><mo>&#x2234;</mo></math> side  =  a  =  4
<math xmlns = "http://www.w3.org/1998/Math/MathML"><mo>&#x2234;</mo></math>  area  =  4<math xmlns = "http://www.w3.org/1998/Math/MathML"><mo>&#xD7;</mo></math> 4 =  16
<math xmlns = "http://www.w3.org/1998/Math/MathML"><mo>&#x2234;</mo></math> 2 <math xmlns = "http://www.w3.org/1998/Math/MathML"><mo>&#xD7;</mo></math> area  =  16 <math xmlns = "http://www.w3.org/1998/Math/MathML"><mo>&#xD7;</mo></math> 2  =  32
New area  =  32
New side  =  <math xmlns = "http://www.w3.org/1998/Math/MathML"><msqrt><mn>32</mn></msqrt><mo> = </mo><msqrt><mn>4</mn><mo>&#xD7;</mo><mn>8</mn></msqrt><mo> = </mo><mn>2</mn><msqrt><mn>8</mn></msqrt></math>
New diagonal  =  <math xmlns = "http://www.w3.org/1998/Math/MathML"><mn>2</mn><msqrt><mn>8</mn></msqrt><mo>&#xD7;</mo><msqrt><mn>2</mn></msqrt><mo> = </mo><mn>2</mn><msqrt><mn>8</mn><mo>&#xD7;</mo><mn>2</mn></msqrt><mo> = </mo><mn>2</mn><msqrt><mn>16</mn></msqrt><mo> = </mo><mn>2</mn><mo>&#xD7;</mo><mn>4</mn></math>  =  8cm

</pre>

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