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$\frac{1}{|3 x + 1|} > 1$ এর সমাধান হলো- (The solution of $\frac{1}{|3 x + 1|} > 1$ is-)

(- \infty, \frac{1}{3}) \cup (1, \infty)

x > \frac{1}{3}

0 < x < \frac{2}{3}

(0, \frac{1}{3}) \cup (\frac{1}{3}, \frac{2}{3})

ANS : 4

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