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2^{2} + 4^{2} + 6^{2} + . . . . . . . . . + (2 n)^{2} = ?

\frac{1}{2} n (2 n + 2) (2 n + 1)

\frac{1}{3} n (n + 1) (2 n + 1)

\frac{2}{3} n (n + 1) (2 n + 1)

\frac{3}{2} n (n + 1) (2 n + 1)

None

ANS : 3

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