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Question
50 m মিটার দূরত্ব অতিক্রম করতে একখানি গাড়ির বেগ 10 m/s হতে 20 m/s হয় । আরও 200 m যাবার পর তার বেগ কত হবে?
30 m/s
20 m/s
40 m/s
50 m/s
None
ANSWER : 3
Descrption
<p>প্রথম ক্ষেত্রে, u=10ms-1 ,V=20ms-1, s=50m</p><p>আমরা জানি,V^2=U^2+2as</p><p> বা, 20^2=10^2+2×a×50</p><p> বা, 400=100+100a</p><p> বা, 100a=300</p><p> বা, a=3ms-2</p><p>আবার, দ্বিতীয় ক্ষেত্রে, </p><p> U=20ms-1, S=200m</p><p> এখন, V^2=U^2+2as</p><p> =20^2+2×3×200</p><p> =400+1200</p><p> বা, V^2=1600</p><p> বা, V=√1600</p><p> বা, V=40ms-1</p>
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