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y = \tan^{- 1} \frac{4 x}{1 - 4 x^{2}}

\frac{d y}{d x}

সমান কত?

\frac{4}{1 + 4 x^{2}}

\frac{- 4}{1 - 4 x^{2}}

\frac{4}{1 - 4 x^{2}}

\frac{1}{4 x^{2} - 1}

ANS : 1

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