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1 + (1+2) + (1 + 2 + 3) + ------ + n তম পদ পর্যন্ত = ?

\frac{1}{6} n (n + 1) (2 n + 1)

\frac{1}{2} n (n + 1) (n + 2)

\frac{1}{6} n (n + 1) (n + 2)

\frac{1}{6} n (n + 1) (n + 2) (n + 3)

ANS : 3

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