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c o t^{2} θ - (\sqrt{3} + 1) c o t θ + \sqrt{3} = 0, 0 < θ < \frac{π}{2}, θ = ?

\frac{π}{6}, \frac{π}{3}

\frac{π}{4}, \frac{π}{3}

\frac{π}{6}, \frac{π}{5}

\frac{π}{6}, \frac{π}{4}

ANS : 4

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