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y = mx + c রেখাটি

x^{2} + y^{2} = a^{2}

বৃত্তটির স্পর্শক হবে , যদি -

c = \pm \sqrt{1 + m^{2}}

c = - a \sqrt{1 - m^{2}}

c = a \sqrt{1 - m^{2}}

c = \pm a \sqrt{1 - m^{2}}

c = \sqrt{1 - m^{2}}

ANS : 1

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