এককের একটি জটিল ঘনমূল হলে এর মান হবে-
Created: 2 years ago |
Updated: 7 months ago
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এককের একটি জটিল ঘনমূলকে নিম্নরূপে প্রকাশ করা যায়:
ϖ = e^(iπ/3)
সুতরাং,
(1 + ϖ - ϖ^2)(ϖ + ϖ^2 - 1)(ϖ^2 + 1 - ϖ) = (1 + e^(iπ/3) - e^(-iπ/3))(e^(iπ/3) + e^(-iπ/3) - 1)(e^(-iπ/3) + e^(iπ/3) - e^(iπ/3))
= (2e^(iπ/3))(2e^(-iπ/3))(2e^(-2iπ/3))
= 8e^(iπ)
= 8e^(i(π + 2π))
= 8e^(2πi)
= 8(1)
= 8
অতএব, উত্তর হল 8।
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